In a double-slit experiment,green light (5303 | vedclass

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(B) For diffraction,the position of the $n^{	ext{th}}$ minima is given by $y_n = \frac{n D \lambda}{a}$.Given: $\lambda = 5303\,\mathring{A} = 5303 \

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$05$

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(B) For diffraction,the position of the $n^{	ext{th}}$ minima is given by $y_n = \frac{n D \lambda}{a}$.Given: $\lambda = 5303\,\mathring{A} = 5303 	imes 10^{-10}\,m$,$a = 4.05\,\mu m = 4.05 	imes 10^{-6}\,m$,$d = 19.44\,\mu m = 19.44 	imes 10^{-6}\,m$.Position of $1^{	ext{st}}$ diffraction minima $(y_1)$: $y_1 = \frac{D \lambda}{a}$.Position of $2^{	ext{nd}}$ diffraction minima $(y_2)$: $y_2 = \frac{2 D \lambda}{a}$.For interference,the condition for bright fringes is path difference $\Delta x = m \lambda$,where $\Delta x = \frac{d y}{D}$.Thus,$m = \frac{d y}{D \lambda}$.At $y_1 = \frac{D \lambda}{a}$,the order of interference fringe is $m_1 = \frac{d}{D \lambda} \cdot \frac{D \lambda}{a} = \frac{d}{a} = \frac{19.44}{4.05} = 4.8$.At $y_2 = \frac{2 D \lambda}{a}$,the order of interference fringe is $m_2 = \frac{d}{D \lambda} \cdot \frac{2 D \lambda}{a} = \frac{2d}{a} = 2 	imes 4.8 = 9.6$.The bright fringes between $y_1$ and $y_2$ correspond to integer values of $m$ such that $4.8 These integers are $m = 5, 6, 7, 8, 9$.There are $5$ such bright fringes.

In a double-slit experiment,green light $(5303\,\mathring{A})$ falls on a double slit having a separation of $19.44\,\mu m$ and a width of $4.05\,\mu m$. The number of bright fringes between the first and the second diffraction minima is

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